
/**
* 矩阵的数乘,结果矩阵行列数不变 c[i][j] = num * a[i][j]
*
* @param num
* @return
*/
public Matrix multiplyNum(double num) {
int cRow = this.matrixData.length;
int cColumn = this.matrixData[0].length;
double[][] cData = new double[cRow][cColumn];
for (int i = 0; i < cRow; i++) {
for (int j = 0; j < cColumn; j++) {
cData[i][j] = num * this.matrixData[i][j];
}
}
return new Matrix(cData);
}


