[java]代码库
public class ListAllRunningThread {
/**
* 列出所有线程的信息
*/
public static void list(){
//获取当前线程所属线程组的父线程组
ThreadGroup root = Thread.currentThread().getThreadGroup().getParent();
//不断循环,直到找到根线程组
while (root.getParent() != null) {
root = root.getParent();
}
//访问根线程组下的线程
visit(root, 0);
}
/**
* 递归的显示线程组中的线程
* @param group
* @param level
*/
private static void visit(ThreadGroup group, int level) {
// 获取group线程组中活动线程的估计数
int numThreads = group.activeCount();
Thread[] threads = new Thread[numThreads];
// 把此线程组中的所有活动线程复制到指定数组中。
// false表示不包括作为此线程组的子组的线程组中的线程。
numThreads = group.enumerate(threads, false);
// 遍历活动线程数组,打印它们的名字
for (int i=0; i<numThreads; i++) {
// Get thread
Thread thread = threads[i];
for (int j=0; j<level; j++){
System.out.print(" ");
}
System.out.println("" + thread.getName());
}
// 获取group线程组中活动子线程组的估计数
int numGroups = group.activeGroupCount();
ThreadGroup[] groups = new ThreadGroup[numGroups];
// 把对此线程组中的所有活动子组的引用复制到指定数组中。
numGroups = group.enumerate(groups, false);
// 递归的访问子线程组中的线程
for (int i=0; i<numGroups; i++) {
visit(groups[i], level+1);
}
}
/**
* @param args
*/
public static void main(String[] args) {
//建立一个线程组
ThreadGroup group1 = new ThreadGroup("ThreadGroup-1");
//建立3个线程并启动
Thread[] threads1 = new Thread[3];
for (int i=1; i<4; i++){
//新的线程属于group1线程组,以ThreadA为运行对象,名字为"group1-ThreadA-i"
threads1[i-1] = new Thread(group1, new ThreadA(i*2000), "group1-ThreadA-" + i);
threads1[i-1].start();
}
//建立另一个线程组,属于group1线程组
ThreadGroup group2 = new ThreadGroup(group1, "ThreadGroup-2");
//建立3个线程并启动
Thread[] threads2 = new Thread[3];
for (int i=1; i<4; i++){
//新的线程属于group2线程组,以ThreadA为运行对象,名字为"group2-ThreadA-i"
threads2[i-1] = new Thread(group2, new ThreadA(i*1000), "group2-ThreadA-" + i);
threads2[i-1].start();
}
//列出所有活动的线程的名字
System.out.println("当前虚拟机中所有正在运行的线程:");
ListAllRunningThread.list();
}
static class ThreadA extends Thread{
private long sleepTime = 100;
public ThreadA(long time){
this.sleepTime = time;
}
public void run(){
try {
Thread.sleep(this.sleepTime);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}