c++ 计算n天后的日期

[c++]代码库

#include <iostream>

class CDate {
private:
	int m_nDay; // Range: 1 - 30 (lets assume all months have 30 days!)
	int m_nMonth; // Range: 1 - 12
	int m_nYear;

	void AddDays(int nDaysToAdd) {
		m_nDay += nDaysToAdd;

		if (m_nDay > 30) {
			AddMonths(m_nDay / 30);

			m_nDay %= 30; // rollover 30th -> 1st
		}
	}

	void AddMonths(int nMonthsToAdd) {
		m_nMonth += nMonthsToAdd;

		if (m_nMonth > 12) {
			AddYears(m_nMonth / 12);

			m_nMonth %= 12; // rollover dec -> jan
		}
	}

	void AddYears(int m_nYearsToAdd) {
		m_nYear += m_nYearsToAdd;
	}

public:

	// Constructor that initializes the object to a day, month and year
	CDate(int nDay, int nMonth, int nYear) :
			m_nDay(nDay), m_nMonth(nMonth), m_nYear(nYear) {
	}
	;

	CDate operator +(int nDaysToAdd) {
		CDate newDate(m_nDay, m_nMonth, m_nYear);
		newDate.AddDays(nDaysToAdd);

		return newDate;
	}

	void DisplayDate() {
		std::cout << m_nDay << " / " << m_nMonth << " / " << m_nYear;
	}
};

int main() {
	// Instantiate and initialize a date object to 25 May 2008
	CDate mDate(25, 6, 2008);

	std::cout << "The date object is initialized to: ";

	// Display initial date
	mDate.DisplayDate();
	std::cout << std::endl;

	std::cout << "Date after adding 10 days is: ";

	// Adding 10 (days)...
	CDate datePlus10(mDate + 10);

	datePlus10.DisplayDate();

	return 0;
}