hdoj1020简单的字符串处理

[c++]代码库

#include<iostream>
#include<string>
using namespace std;

int main(){
	string s1;
	char ch[10005];
	int m;
	int count1 = 1;
	int count2 = 0;
	cin>>m;
	for(int i = 0; i < m; i++){//依次处理每一行		
		count2 = 0;
		cin>>s1;
		if(s1.length() == 1){
			cout<<s1<<endl;
			continue;
		}
		for(int j = 1; j < s1.length(); j++){//依次处理每个字符		
			if(s1[j] == s1[j - 1]){
				count1++;
			}else {
				if(count1 > 1){
					count2++;
					//ch[count2 - 1] = (char)(count1 + 48);
					char temp[10];
					sprintf(temp, "%d", count1);//count1的值可能大于个位数
					for(int k = 0; temp[k] != '\0'; k++, count2++){
						ch[count2 - 1] = temp[k];
					}
					count2--;
				}			
				count2++;
				ch[count2 - 1] = s1[j - 1];
				count1 = 1;
			}
		}
		if(count1 != 1){
			count2++;
			//ch[count2 - 1] = (char)(count1 + 48);
			char temp[10];
			sprintf(temp, "%d", count1);
			for(int k = 0; temp[k] != '\0'; k++, count2++){
				ch[count2 - 1] = temp[k];
			}
			count2--;//很多的count2++与count2--只是为了保持逻辑的直接性
			count2++;
			ch[count2 - 1] = s1[s1.length() - 1];
			count1 = 1;
		}else{
			count2++;
			ch[count2 -1] = s1[s1.length() - 1];
		}
		ch[count2] = '\0';
		cout<<ch<<endl;
	}
}