显示某路径下所有文件类型的文件数量和文件夹的数量

[python]代码库

import os


def list_file(folder):
    folder_count = 0
    houzhui_num = 0
    houzhui = ''
    all_houzhui = []
    all_houzhui_num = [] # 对应后缀名的文件数量
    all_files = os.listdir(folder)
    for each in all_files:
        if '.' in each: # 如果此项是文件
            file = os.path.splitext(each)
            houzhui = file[1] # 每一个文件的后缀名，这里例如.exe
            if houzhui not in all_houzhui: # 如果all_houzhui里没有.exe项
                all_houzhui.append(houzhui) # 就将.exe追加进all_houzhui
                houzhui_num = 1
                all_houzhui_num.append(houzhui_num) #
            else: # 如果all_houzhui里有.exe项
               all_houzhui_num[all_houzhui.index(houzhui)] += 1 # 对应后缀名的此项数字增加1
        else: # 如果此项不是文件
            folder_count += 1
    for each in all_houzhui:
        print('文件类型为%s的文件数量为：%d' % (each,all_houzhui_num[all_houzhui.index(each)]))
    print('文件夹数量：%d' % folder_count)



list_file('G:\\迅雷下载')

[代码运行效果截图]