#include<stdio.h> |
int fun( int n) |
{ |
if (n <= 1) |
return n; |
else |
return fun(n-1) + fun(n-2); |
} |
|
int main() |
{ |
int n; |
printf ( "请输入要输出斐波那契数列n:" ); |
scanf ( "%d" ,&n); |
int i; |
printf ( "第 %d 项是:%d\n" , n, fun(n)); |
return 0; |
} |
by: 发表于:2017-12-13 10:33:51 顶(0) | 踩(0) 回复
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