计算两日期之间的工作天数, 过滤休息日

[python]代码库

import datetime
# 计算两个日期之间的工作日数,非天数.
class workDays():
    def __init__(self, start_date, end_date, days_off=None):
        """days_off:休息日,默认周六日, 以0(星期一)开始,到6(星期天)结束, 传入tupple
        没有包含法定节假日,
        """
        self.start_date = start_date
        self.end_date = end_date
        self.days_off = days_off
        if self.start_date > self.end_date:
            self.start_date,self.end_date = self.end_date, self.start_date
        if days_off is None:
            self.days_off = 5,6
        # 每周工作日列表
        self.days_work = [x for x in range(7) if x not in self.days_off]

    def workDays(self):
        """实现工作日的 iter, 从start_date 到 end_date , 如果在工作日内,yield 日期
        """
        # 还没排除法定节假日
        tag_date = self.start_date
        while True:
            if tag_date > self.end_date:
                break
            if tag_date.weekday() in self.days_work:
                yield tag_date
            tag_date += datetime.timedelta(days=1)

    def daysCount(self):
        """工作日统计,返回数字"""
        return len(list(self.workDays()))

    def weeksCount(self, day_start=0):
        """统计所有跨越的周数,返回数字
        默认周从星期一开始计算
        """
        day_nextweek = self.start_date
        while True:
            if day_nextweek.weekday() == day_start:
                break
            day_nextweek += datetime.timedelta(days=1)
        # 区间在一周内
        if day_nextweek > self.end_date:
            return 1
        weeks = ((self.end_date - day_nextweek).days + 1)/7
        weeks = int(weeks)
        if ((self.end_date - day_nextweek).days + 1)%7:
            weeks += 1
        if self.start_date < day_nextweek:
            weeks += 1
        return weeks

[代码运行效果截图]