找出n位整数中每一位数的n次幂之和与原数相同的数。n=3时就是水仙花数

[c#]代码库

using System;

namespace ConsoleApplication1
{
    class Program
    {
        static void Main(string[] args)
        {
            Console.Write("输入整数幂的次数： n = ");
            int n = int.Parse(Console.ReadLine());
            MyApp(n);
            Console.ReadLine();
        }
        /// <summary>
        /// n位整数的每一位数字的n次幂之和与原数相等
        /// </summary>
        /// <param name="n">整数的位数（2<n<9）</param>
        public static void MyApp(int n)
        {
            int i,l = 1, m = 10;
            for(i=0;i<n-1;i++)
            {
                l *= 10;
                m *= 10;
            }                       
            int a, b, c, d, j;
            for(i=l;i<m;i++)
            {
                a = i;
                d = 0;
                while (a > 0)
                {
                    b = a % 10;
                    j = n;
                    c = 1;                    
                    while (j-- > 0)
                        c *= b;
                    d += c;
                    a /= 10;
                }
                if (d == i)
                    Console.WriteLine("{0,12}", i);
            }
        }
    }
}