java 简单Dice问题（随机数的运用）

[java]代码库

/**
 * Dice Write a program that simulates rolling two dice using the following
 * steps: 1. Prompt the user for the number of sides for two dice. 2. “Roll” the
 * dice three times by generating a random number between 1 (inclusive) and the
 * number of sides (inclusive). 3. Keep track of the sum of the rolls for each
 * die and output the sum and average for each die.
 * 
 * Sample Output: How many sides does die 1 have? 6 How many sides does die 2
 * have? 20 Die 1 first roll = 5. Die 2 first roll = 14. Die 1 second roll = 1.
 * Die 2 second roll = 20. Die 1 third roll = 3. Die 2 third roll = 9. Die 1
 * rolled a total of 9 and rolled 3 on average. Die 2 rolled a total of 43 and
 * rolled 14.333 on average.
 * 
 * @author jianfeng
 * 
 */
public class Dice {

	public static void main(String[] args) {
		int[][] dice = new int[3][2];
		int first = 6;
		int second = 20;

		for (int i = 0; i < 3; i++) {
			dice[i][0] = (int) ((Math.random() * first) + 1); // 第一个骰子三次滚动值
			dice[i][1] = (int) ((Math.random() * second) + 1);
			; // 第二个骰子三次滚动值
		}

		// 计算总数
		int sum1 = 0;
		int sum2 = 0;
		for (int i = 0; i < 3; i++) {
			sum1 += dice[i][0];
			sum2 += dice[i][1];
		}

		// 计算平均值
		float avg1 = (float) sum1 / 3;
		float avg2 = (float) sum2 / 3;

		// 输出
		System.out.println("How many sides does die 1 have?" + first);
		System.out.println("How many sides does die 2 have?" + second);
		System.out.println("Die 1 first roll = " + dice[0][0]);
		System.out.println("Die 2 first roll = " + dice[0][1]);
		System.out.println("Die 1 second roll = " + dice[1][0]);
		System.out.println("Die 2 second roll = " + dice[1][1]);
		System.out.println("Die 1 third roll = " + dice[2][0]);
		System.out.println("Die 2 third roll = " + dice[2][1]);
		System.out.println("Die 1 rolled a total of " + sum1 + " and rolled "
				+ avg1 + " on average");
		System.out.println("Die 2 rolled a total of " + sum2 + " and rolled "
				+ avg2 + " on average");

	}
}

[代码运行效果截图]