会python真的可以为所欲为0(回)
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每天面对着电脑屏幕，敲打键盘。我所面对的并不只是代码，而是一种生活方式。0(回)
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鸽子
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875天前#include <stdlib.h> |
#include <stdio.h> |
#include <string.h> |
#define ENCRYPT 1 |
#define DECRYPT 0 |
static void printHex ( char *cmd, int len ); |
static void printArray ( const char *In, int len ); |
static void F_func ( bool In[32], const bool Ki[48] ); // f函数 |
static void S_func ( bool Out[32], const bool In[48] ); // S盒代替 |
static void Transform ( bool *Out, bool *In, const char *Table, int len ); // 变换 |
static void Xor ( bool *InA, const bool *InB, int len ); // 异或 |
static void RotateL ( bool *In, int len, int loop ); // 循环左移 |
static void ByteToBit ( bool *Out, const char *In, int bits ); // 字节组转换成位组 |
static void BitToByte ( char *Out, const bool *In, int bits ); // 位组转换成字节组 |
// 16位子密钥 |
static bool SubKey[16][48]; |
// 64位经过PC1转换为56位 (PC-1) |
const static char PC1_Table[56] = |
{ |
57, 49, 41, 33, 25, 17, 9, |
1, 58, 50, 42, 34, 26, 18, |
10, 2, 59, 51, 43, 35, 27, |
19, 11, 3, 60, 52, 44, 36, |
63, 55, 47, 39, 31, 23, 15, |
7, 62, 54, 46, 38, 30, 22, |
14, 6, 61, 53, 45, 37, 29, |
21, 13, 5, 28, 20, 12, 4 |
}; |
// 左移 |
const static char LOOP_Table[16] = |
{ |
1, 1, 2, 2, 2, 2, 2, 2, |
1, 2, 2, 2, 2, 2, 2, 1 |
}; |
// 排列选择 2 (PC-2) |
const static char PC2_Table[48] = |
{ |
14, 17, 11, 24, 1, 5, |
3, 28, 15, 6, 21, 10, |
23, 19, 12, 4, 26, 8, |
16, 7, 27, 20, 13, 2, |
41, 52, 31, 37, 47, 55, |
30, 40, 51, 45, 33, 48, |
44, 49, 39, 56, 34, 53, |
46, 42, 50, 36, 29, 32 |
}; |
// Ri_1（32位）经过变换E后膨胀为48位 (E) void F_func |
static const char E_Table[48] = |
{ |
32, 1, 2, 3, 4, 5, |
4, 5, 6, 7, 8, 9, |
8, 9, 10, 11, 12, 13, |
12, 13, 14, 15, 16, 17, |
16, 17, 18, 19, 20, 21, |
20, 21, 22, 23, 24, 25, |
24, 25, 26, 27, 28, 29, |
28, 29, 30, 31, 32, 1 |
}; |
// 8个4比特合并为32比特的排列 P |
const static char P_Table[32] = |
{ |
16, 7, 20, 21, |
29, 12, 28, 17, |
1, 15, 23, 26, |
5, 18, 31, 10, |
2, 8, 24, 14, |
32, 27, 3, 9, |
19, 13, 30, 6, |
22, 11, 4, 25, |
}; |
// 经过S盒 S-boxes |
const static char S_Box[8][4][16] = |
{ |
{ |
// S1 |
{ 14, 4, 13, 1, 2, 15, 11, 8, 3, 10, 6, 12, 5, 9, 0, 7 }, |
{ 0, 15, 7, 4, 14, 2, 13, 1, 10, 6, 12, 11, 9, 5, 3, 8 }, |
{ 4, 1, 14, 8, 13, 6, 2, 11, 15, 12, 9, 7, 3, 10, 5, 0 }, |
{ 15, 12, 8, 2, 4, 9, 1, 7, 5, 11, 3, 14, 10, 0, 6, 13 } |
}, |
{ |
// S2 |
{ 15, 1, 8, 14, 6, 11, 3, 4, 9, 7, 2, 13, 12, 0, 5, 10 }, |
{ 3, 13, 4, 7, 15, 2, 8, 14, 12, 0, 1, 10, 6, 9, 11, 5 }, |
{ 0, 14, 7, 11, 10, 4, 13, 1, 5, 8, 12, 6, 9, 3, 2, 15 }, |
{ 13, 8, 10, 1, 3, 15, 4, 2, 11, 6, 7, 12, 0, 5, 14, 9 } |
}, |
{ |
// S3 |
{ 10, 0, 9, 14, 6, 3, 15, 5, 1, 13, 12, 7, 11, 4, 2, 8 }, |
{ 13, 7, 0, 9, 3, 4, 6, 10, 2, 8, 5, 14, 12, 11, 15, 1 }, |
{ 13, 6, 4, 9, 8, 15, 3, 0, 11, 1, 2, 12, 5, 10, 14, 7 }, |
{ 1, 10, 13, 0, 6, 9, 8, 7, 4, 15, 14, 3, 11, 5, 2, 12 } |
}, |
{ |
// S4 |
{ 7, 13, 14, 3, 0, 6, 9, 10, 1, 2, 8, 5, 11, 12, 4, 15 }, |
{ 13, 8, 11, 5, 6, 15, 0, 3, 4, 7, 2, 12, 1, 10, 14, 9 }, |
{ 10, 6, 9, 0, 12, 11, 7, 13, 15, 1, 3, 14, 5, 2, 8, 4 }, |
{ 3, 15, 0, 6, 10, 1, 13, 8, 9, 4, 5, 11, 12, 7, 2, 14 } |
}, |
{ |
// S5 |
{ 2, 12, 4, 1, 7, 10, 11, 6, 8, 5, 3, 15, 13, 0, 14, 9 }, |
{ 14, 11, 2, 12, 4, 7, 13, 1, 5, 0, 15, 10, 3, 9, 8, 6 }, |
{ 4, 2, 1, 11, 10, 13, 7, 8, 15, 9, 12, 5, 6, 3, 0, 14 }, |
{ 11, 8, 12, 7, 1, 14, 2, 13, 6, 15, 0, 9, 10, 4, 5, 3 } |
}, |
{ |
// S6 |
{ 12, 1, 10, 15, 9, 2, 6, 8, 0, 13, 3, 4, 14, 7, 5, 11 }, |
{ 10, 15, 4, 2, 7, 12, 9, 5, 6, 1, 13, 14, 0, 11, 3, 8 }, |
{ 9, 14, 15, 5, 2, 8, 12, 3, 7, 0, 4, 10, 1, 13, 11, 6 }, |
{ 4, 3, 2, 12, 9, 5, 15, 10, 11, 14, 1, 7, 6, 0, 8, 13 } |
}, |
{ |
// S7 |
{ 4, 11, 2, 14, 15, 0, 8, 13, 3, 12, 9, 7, 5, 10, 6, 1 }, |
{ 13, 0, 11, 7, 4, 9, 1, 10, 14, 3, 5, 12, 2, 15, 8, 6 }, |
{ 1, 4, 11, 13, 12, 3, 7, 14, 10, 15, 6, 8, 0, 5, 9, 2 }, |
{ 6, 11, 13, 8, 1, 4, 10, 7, 9, 5, 0, 15, 14, 2, 3, 12 } |
}, |
{ |
// S8 |
{ 13, 2, 8, 4, 6, 15, 11, 1, 10, 9, 3, 14, 5, 0, 12, 7 }, |
{ 1, 15, 13, 8, 10, 3, 7, 4, 12, 5, 6, 11, 0, 14, 9, 2 }, |
{ 7, 11, 4, 1, 9, 12, 14, 2, 0, 6, 10, 13, 15, 3, 5, 8 }, |
{ 2, 1, 14, 7, 4, 10, 8, 13, 15, 12, 9, 0, 3, 5, 6, 11 } |
} |
}; |
// 初始排列 (IP) |
const static char IP_Table[64] = |
{ |
58, 50, 42, 34, 26, 18, 10, 2, |
60, 52, 44, 36, 28, 20, 12, 4, |
62, 54, 46, 38, 30, 22, 14, 6, |
64, 56, 48, 40, 32, 24, 16, 8, |
57, 49, 41, 33, 25, 17, 9, 1, |
59, 51, 43, 35, 27, 19, 11, 3, |
61, 53, 45, 37, 29, 21, 13, 5, |
63, 55, 47, 39, 31, 23, 15, 7 |
}; |
// L16与R16合并后经过IP_1的最终排列 (IP**-1) |
const static char IPR_Table[64] = |
{ |
40, 8, 48, 16, 56, 24, 64, 32, |
39, 7, 47, 15, 55, 23, 63, 31, |
38, 6, 46, 14, 54, 22, 62, 30, |
37, 5, 45, 13, 53, 21, 61, 29, |
36, 4, 44, 12, 52, 20, 60, 28, |
35, 3, 43, 11, 51, 19, 59, 27, |
34, 2, 42, 10, 50, 18, 58, 26, |
33, 1, 41, 9, 49, 17, 57, 25 |
}; |
void Des_SetKey ( const char Key[8] ); //生成子密钥 |
void Des_Run ( char Out[8], char In[8], bool Type ); //DES算法 |
void main ( int argc, char *argv[] ) |
{ |
char key[12]={1,2,3,4,5,6,7,8}; |
char str[12]="Hello"; |
char str2[12]; |
//printArray( PC2_Table, sizeof(PC2_Table)/sizeof(PC2_Table[0]) ); |
printf ( "Before encrypting: " ); |
puts ( str ); |
Des_SetKey ( key ); |
memset ( str2, 0, sizeof ( str2 ) ); |
Des_Run ( str2, str, ENCRYPT ); |
printf ( "After encrypting: " ); |
printHex ( str2, 8 ); |
memset ( str, 0, sizeof ( str ) ); |
printf ( "After decrypting: " ); |
Des_Run ( str, str2, DECRYPT ); |
puts ( str ); |
} |
void Des_SetKey ( const char Key[8] ) |
{ |
int i; |
static bool K[64], *KL = &K[0], *KR = &K[28]; |
ByteToBit ( K, Key, 64 ); //转换为二进制 |
Transform ( K, K, PC1_Table, 56 ); //64比特的密钥K，经过PC-1后，生成56比特的串。 |
//生成16个子密钥 |
for ( i=0; i<16; i++ ) |
{ |
//循环左移，合并 |
RotateL ( KL, 28, LOOP_Table[i] ); |
RotateL ( KR, 28, LOOP_Table[i] ); |
Transform ( SubKey[i], K, PC2_Table, 48 ); |
} |
} |
void Des_Run ( char Out[8], char In[8], bool Type ) |
{ |
int i; |
static bool M[64], tmp[32], *Li = &M[0], *Ri = &M[32]; |
//转换为64位的数据块 |
ByteToBit ( M, In, 64 ); |
//IP置换 （初始） |
Transform ( M, M, IP_Table, 64 ); |
//该比特串被分为32位的L0和32位的R0两部分。 |
if ( Type == ENCRYPT ) |
{ |
//16轮置换 |
for ( i=0; i<16; i++ ) |
{ |
memcpy ( tmp, Ri, 32 ); |
// R[i] = L[i-1] xor f(R[i-1], K[i]) |
F_func ( Ri, SubKey[i] ); |
// 2.4.6 Exclusive-or the resulting value with L[i-1]. |
// R[I]=P XOR L[I-1] |
Xor ( Ri, Li, 32 ); |
// L[i] = R[i-1] |
memcpy ( Li, tmp, 32 ); |
} |
} |
else |
{ |
// 如果解密则反转子密钥顺序 |
for ( i=15; i>=0; i-- ) |
{ |
memcpy ( tmp, Li, 32 ); |
F_func ( Li, SubKey[i] ); |
Xor ( Li, Ri, 32 ); |
memcpy ( Ri, tmp, 32 ); |
} |
} |
//R16与L16合并成64位的比特串。R16一定要排在L16前面。R16与L16合并后成的比特串，经过置换IP-1后所得的比特串就是密文。 |
Transform ( M, M, IPR_Table, 64 ); |
BitToByte ( Out, M, 64 ); |
} |
//将32比特的输入再转化为32比特的输出 |
void F_func ( bool In[32], const bool Ki[48] ) |
{ |
static bool MR[48]; |
//输入Ri-1(32比特)经过变换E后，膨胀为48比特 |
Transform ( MR, In, E_Table, 48 ); |
//异或 |
Xor ( MR, Ki, 48 ); |
//膨胀后的比特串分为8组，每组6比特。各组经过各自的S盒后，又变为4比特(具体过程见后)，合并后又成为32比特。 |
S_func ( In, MR ); |
//该32比特经过P变换后，输出的比特串才是32比特的f (Ri-1,Ki)。 |
Transform ( In, In, P_Table, 32 ); |
} |
void S_func ( bool Out[32], const bool In[48] ) |
{ |
char j,m,n; |
//膨胀后的比特串分为8组，每组6比特。 |
for ( j=0; j<8; j++,In+=6,Out+=4 ) |
{ |
//在其输入In[0],In[1],In[2],In[3],In[4],In[5]中，计算出m=In[0]*2+In[5], n=In[4]+In[3]*2+In[2]*4+In[1]*8，再从Sj表中查出m行，n列的值Smn。将Smn化为二进制，即得Si盒的输出。 |
m = ( In[0]<<1 ) + In[5]; |
n = ( In[1]<<3 ) + ( In[2]<<2 ) + ( In[3]<<1 ) + In[4]; |
ByteToBit ( Out, &S_Box[ ( int ) j][ ( int ) m][ ( int ) n], 4 ); |
} |
} |
// 打印指定位置指定长度HEX值 |
static void printHex ( char *cmd, int len ) |
{ |
int i; |
for ( i=0; i<len; i++ ) |
{ |
printf ( "[%02X]", ( unsigned char ) cmd[i] ); |
} |
printf ( "\n" ); |
} |
// 打印数组测试用 |
static void printArray ( const char *In, int len ) |
{ |
int i; |
char tmp[256]; |
memset ( tmp, 0, sizeof ( tmp ) ); |
for ( i=0; i<len; i++ ) |
{ |
tmp[ ( int ) In[i]]=In[i]; |
} |
for ( i=0; i<len; i++ ) |
{ |
printf ( "[%02d]", ( unsigned char ) tmp[i] ); |
} |
printf ( "\n" ); |
} |
void Transform ( bool *Out, bool *In, const char *Table, int len ) |
{ |
int i; |
static bool tmp[256]; |
for ( i=0; i<len; i++ ) |
{ |
tmp[i] = In[ Table[i]-1 ]; |
} |
memcpy ( Out, tmp, len ); |
} |
void Xor ( bool *InA, const bool *InB, int len ) |
{ |
int i; |
for ( i=0; i<len; i++ ) |
{ |
InA[i] ^= InB[i]; |
} |
} |
void RotateL ( bool *In, int len, int loop ) |
{ |
static bool tmp[256]; // Sample: loop=2 |
memcpy ( tmp, In, loop ); // In=12345678 tmp=12 |
memcpy ( In, In+loop, len-loop ); // In=345678 |
memcpy ( In+len-loop, tmp, loop ); // In=34567812 |
} |
// Sample: |
// In = [0x01] |
// Out = [0x01] [0x00] [0x00] [0x00] [0x00] [0x00] [0x00] [0x00] |
void ByteToBit ( bool *Out, const char *In, int bits ) |
{ |
int i; |
for ( i=0; i<bits; i++ ) |
{ |
// In[i]的第N位右移N位并和0x01按位"与"运算(N=1~8) |
Out[i] = ( In[i/8]>> ( i%8 ) ) & 1; |
} |
} |
void BitToByte ( char *Out, const bool *In, int bits ) |
{ |
int i; |
memset ( Out, 0, ( bits+7 ) /8 ); |
for ( i=0; i<bits; i++ ) |
{ |
Out[i/8] |= In[i]<< ( i%8 ); |
} |
} |
