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云代码 - c代码库

老鼠走迷宫算法 迷宫回溯算法 c语言算法

2012-11-02 作者: 小蜜锋举报

[c]代码库

#include <stdio.h>
#include <stdlib.h>
 
int visit ( int, int );
 
int maze[7][7] = {{2, 2, 2, 2, 2, 2, 2},
    {2, 0, 0, 0, 0, 0, 2},
    {2, 0, 2, 0, 2, 0, 2},
    {2, 0, 0, 2, 0, 2, 2},
    {2, 2, 0, 2, 0, 2, 2},
    {2, 0, 0, 0, 0, 0, 2},
    {2, 2, 2, 2, 2, 2, 2}
};
 
int startI = 1, startJ = 1;  // 入口
int endI = 5, endJ = 5;  // 出口
int success = 0;
 
int main ( void )
{
    int i, j;
 
    printf ( "显示迷宫:\n" );
    for ( i = 0; i < 7; i++ )
    {
        for ( j = 0; j < 7; j++ )
            if ( maze[i][j] == 2 )
                printf ( "█" );
            else
                printf ( "  " );
        printf ( "\n" );
    }
 
    if ( visit ( startI, startJ ) == 0 )
        printf ( "\n没有找到出口!\n" );
    else
    {
        printf ( "\n显示路径:\n" );
        for ( i = 0; i < 7; i++ )
        {
            for ( j = 0; j < 7; j++ )
            {
                if ( maze[i][j] == 2 )
                    printf ( "█" );
                else if ( maze[i][j] == 1 )
                    printf ( "◇" );
                else
                    printf ( "  " );
            }
            printf ( "\n" );
        }
    }
 
    return 0;
}
 
int visit ( int i, int j )
{
    maze[i][j] = 1;
 
    if ( i == endI && j == endJ )
        success = 1;
 
    if ( success != 1 && maze[i][j+1] == 0 ) visit ( i, j+1 );
    if ( success != 1 && maze[i+1][j] == 0 ) visit ( i+1, j );
    if ( success != 1 && maze[i][j-1] == 0 ) visit ( i, j-1 );
    if ( success != 1 && maze[i-1][j] == 0 ) visit ( i-1, j );
 
    if ( success != 1 )
        maze[i][j] = 0;
 
    return success;
}

[代码运行效果截图]


老鼠走迷宫算法 迷宫回溯算法 c语言算法


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