从键盘读入个数不确定的整数，并判断读入的正数和负数的个数，输入为0时结束

[java]代码库

public class no1{
 public static void main(String[] args){
  Scanner in=new Scanner(System.in);
  int number,sum=0,count1=0,count2=0;
  double avg;
  do{
   //System.out.println("请随机输入一个整数: ");
   number=in.nextInt();
   if(number>0){
    count1=count1+1;
   }if(number<0){
    count2=count2+1;
   }
   sum=sum+number;
  }while(number!=0);
  System.out.println("正整数的个数为: "+count1);
  System.out.println("负整数的个数为: "+count2);
  avg=(double)sum/(count1+count2);
  System.out.println("这些数的总和是: "+sum);
  System.out.println("这些数的平均值是: "+avg);
 }
}