AI时代，找源码已成为过去式，纪念我过去的十年0(回)
71天前
还有人吗2(回)
89天前会python真的可以为所欲为0(回)
569天前
这里还有人吗2(回)
754天前这里还有人吗0(回)
754天前
每天面对着电脑屏幕，敲打键盘。我所面对的并不只是代码，而是一种生活方式。0(回)
978天前1. String转ASCII码 |
public static String stringToAscii(String value) { |
StringBuffer sbu = new StringBuffer(); |
char[] chars = value.toCharArray(); |
for (int i = 0; i < chars.length; i++) { |
if (i <= chars.length - 1) { |
int ii = chars[i]; |
sbu.append(Integer.toHexString(ii)); |
} else { |
sbu.append((int) chars[i]); |
} |
} |
return sbu.toString(); |
} |
2. ASCII码转String |
public static String asciiToString(String value) { |
if("".equals(value) || value == null){ |
return ""; |
} |
StringBuffer sBuffer = new StringBuffer(); |
char[] chars = value.toCharArray(); |
for (int i = 0; i < chars.length; i = i + 2) { |
if (i < chars.length - 1) { |
int ii = Integer.valueOf( |
Character.toString(chars[i]) + Character.toString(chars[i + 1]), 16); |
sBuffer.append((char) (ii)); |
} |
} |
return sBuffer.toString(); |
} |
|
3. 输入流转字节数组 |
public static String inputStream2Byte(InputStream inputStream) throws IOException { |
ByteArrayOutputStream bos = new ByteArrayOutputStream(); |
byte[] buffer = new byte[1024]; |
int len = -1; |
while ((len = inputStream.read(buffer)) != -1) { |
bos.write(buffer, 0, len); |
} |
bos.close(); |
return new String(bos.toByteArray(), "UTF-8"); |
} |
4. 输入流转字符串 |
public static String InputStreamTOString(InputStream in) throws Exception { |
|
ByteArrayOutputStream outStream = new ByteArrayOutputStream(); |
byte[] data = new byte[1024]; |
int count = -1; |
while ((count = in.read(data, 0, 2048)) != -1) |
outStream.write(data, 0, count); |
|
data = null; |
return new String(outStream.toByteArray()); |
} |
|
5. 判断输入是不是包含中文 |
public static boolean isChinese(char c) { |
Character.UnicodeBlock ub = Character.UnicodeBlock.of(c); |
if (ub == Character.UnicodeBlock.CJK_UNIFIED_IDEOGRAPHS || ub == Character.UnicodeBlock.CJK_COMPATIBILITY_IDEOGRAPHS |
|| ub == Character.UnicodeBlock.CJK_UNIFIED_IDEOGRAPHS_EXTENSION_A || ub == Character.UnicodeBlock.CJK_UNIFIED_IDEOGRAPHS_EXTENSION_B |
|| ub == Character.UnicodeBlock.CJK_SYMBOLS_AND_PUNCTUATION || ub == Character.UnicodeBlock.HALFWIDTH_AND_FULLWIDTH_FORMS |
|| ub == Character.UnicodeBlock.GENERAL_PUNCTUATION) { |
return true; |
} |
return false; |
} |
|
public static boolean isChinese(String strName) { |
char[] ch = strName.toCharArray(); |
for (int i = 0; i < ch.length; i++) { |
char c = ch[i]; |
if (isChinese(c)) { |
return true; |
} |
} |
return false; |
} |
|
6. 检验子网掩码的合法性：子网掩码转化为二进制之后不能全是1，也不能全是0，必须是连续的1或者连续的0，也就是说1和0不能交替出现。 |
实现方式，先将4个整数字段按照每八位拼接起来，软后转化为二进制显示方式，使用正则表达式进行匹配。 |
public static boolean checkMask(String maskStr){ |
String[] ips = maskStr.split("\\."); |
String binaryVal = ""; |
for (int i = 0; i < ips.length; i++) |
{ |
String binaryStr = Integer.toBinaryString(Integer.parseInt(ips[i])); |
Integer times = 8 - binaryStr.length(); |
|
for(int j = 0; j < times; j++) |
{ |
binaryStr = "0" + binaryStr; //补齐八位，每次需要进行八位合并 |
} |
binaryVal += binaryStr; |
} |
Pattern regxPattern = Pattern.compile("^[1]*[0]*$"); |
if(regxPattern.matcher(binaryVal).matches()) |
{ |
return true; |
}else { |
return false; |
} |
} |
|
7. 检查IP的合法性，并转化为整数表示 |
public static boolean validIP(String ip) { |
if (ip == null) { |
return false; |
} |
String IP_REGEX = "\\b((?!\\d\\d\\d)\\d+|1\\d\\d|2[0-4]\\d|25[0-5])\\." |
+ "((?!\\d\\d\\d)\\d+|1\\d\\d|2[0-4]\\d|25[0-5])\\." |
+ "((?!\\d\\d\\d)\\d+|1\\d\\d|2[0-4]\\d|25[0-5])\\." |
+ "((?!\\d\\d\\d)\\d+|1\\d\\d|2[0-4]\\d|25[0-5])\\b"; |
Pattern ipPattern = Pattern.compile(IP_REGEX); |
Matcher matcher = ipPattern.matcher(ip); |
return matcher.matches(); |
} |
|
public static Integer ipString2Int(String strIp){ |
if(!validIP(strIp)) return null; |
|
int[] ip = new int[4]; |
String[] ips = strIp.split("\\."); |
|
ip[0] = Integer.parseInt(ips[0]); |
ip[1] = Integer.parseInt(ips[1]); |
ip[2] = Integer.parseInt(ips[2]); |
ip[3] = Integer.parseInt(ips[3]); |
return (ip[0] << 24) + (ip[1] << 16) + (ip[2] << 8) + ip[3]; |
} |
