判断1000以内回文数

[python]代码库

#求1000以内的回文数
#1 2 3 2 1
# 1~9
#11 22 33 ....
#101 111 121 131...

num = 1
while num < 1000:
    #判断num是不是回文数
    if num < 10:
        print(num)
    elif num >= 10 and num < 100:
        if num % 11 == 0:
            print(num)
    else:
        f = num % 10
        h = num // 100
        if f == h:
            print(num)
    num = num + 1