时间判断

[python]代码库

from datetime import datetime     #直接引用datetime.datetime

def f(n):
    """
    判断n是不是闰年
    是，返回true
    否，返回folse
    """
    g = False
    if (n / 400 == 0) or ((n / 4 == 0) and (n / 100 != 0)):
        g = True
    return g
def main():
    """
    主函数
    """
    x = print('继续运行程序请输入“是”，反之则“否”！')
    while x !="否":
        if x == '是':
            try:
                a = input('请输入日期(****/**/**):')
                b = datetime.strptime(a, '%Y/%m/%d')
                print(b)
                n = b.year
                y = b.month
                r = b.day
                #月份字典            # 包含30天的月份集合
                gg = {1:31,          #_30_ = {4, 6, 9, 11}
                      2:28,          #_31_ = {1, 3, 5, 7, 8, 10, 12}
                      3:31,
                      4:30,
                      5:31,
                      6:30,
                      7:31,
                      8:31,
                      9:30,
                      10:31,
                      11:30,
                      12:31}
                h = 0
                h += r
                for i in range(1, y):
                    h += gg[i]
                    # if i in _30_:
                    #     h += 30
                    # else:
                    #     h += 31
                if y > 2 and f(n) and y > 2:
                    h +=1
                print('这是{}年第{}天！'.format(n,h))
            except ValueError:
                print('请输入正确信息！')