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852天前count = 0 |
# 定义一个字典存储用户名和密码 |
names = {} |
# 定义一个列表存储用户名 |
name_exit = [] |
username = input("username:") |
# 判断输入的用户的用户是否在用户名单中 |
with open("name_login.txt", 'r') as f: |
while True: |
line = f.readline().strip() |
if not line: |
break |
else: |
name = line.split(':')[0] |
passwd = line.split(':')[1] |
names[name] = passwd |
for key in names: |
name_exit.append(key) |
# 判断用户名是否正确,不正确则继续输入 |
while username not in name_exit: |
print("The account is not exit.Check it again.") |
username = input("username:") |
else: |
with open("name_lock.txt", "r") as f: |
lock_name = f.read() |
# 判断用户名是否在锁定文件中，如果在就退出程序 |
if username == lock_name: |
print("Sorry.Your account has been locked.") |
exit() |
else: |
# 3次输入密码的机会 |
while count < 3: |
passwd_input = input("password:") |
# 判断用户名和密码是否有效 |
if passwd_input == names[username]: |
print("Welcome!", username) |
break |
else: |
print("Error,please try again.") |
count += 1 |
# 如果3次输入密码错误，则将用户名添加到锁定文件 |
if count == 3: |
with open("name_lock.txt", "w") as f: |
f.write("%s" % username) |
print("You have tried 3 times,and your account will be locked") |
高级设计师
by: Python自学 发表于：2022-11-16 02:41:06 顶(1) | 踩(1) 回复
name_login.txt
user1:python
user2:Noh346
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