Java解析Json格式数据

[java]代码库

JSONObject obj = new JSONObject(json.toString());  
JSONArray obj2 = obj.getJSONArray("cityInfo");  

得到集合后遍历就可得到一个JSONObject,再调用getString("name");  就行了，下面是完整的代码
[java] view plaincopy
JSONObject obj = new JSONObject(json.toString());  
JSONArray obj2 = obj.getJSONArray("cityInfo");  
for (int i = 0; i < obj2.length(); i++) {  
       JSONObject temp = new JSONObject(obj2.getString(i));  
    System.out.println(temp.getString("cityId"));  
    System.out.println(temp.getString("cityName"));  
}  
System.out.println("============所在省份为=================");  
System.out.println(obj.getString("name"));  

//源代码片段来自云代码http://yuncode.net