public static void main(String[] args) |
{ |
/* 输出这样的图行: |
1*1=1 |
1*2=2 2*2=4 |
1*3=3 2*3=6 3*3=9 |
思想: |
发现第一列的每一行的被乘数都是1,说明内循环从1开始 |
乘数是由外循环实现的,从1开始,随着行数的递增,而逐渐递增。 |
步骤: |
1. 设被乘数变量为x; |
2. 设乘数为y; |
*/ |
|
for ( int y= 1 ;y<= 9 ;y++) |
{ |
for ( int x= 1 ; x<=y; x++) |
{ |
System.out.print(x+ "*" +y+ "=" +x*y+ "\t" ); //不加制表符的话显示的格式不好看 |
} |
System.out.println(); |
} |
} |
//输出结果为: |
1 * 1 = 1 |
1 * 2 = 2 2 * 2 = 4 |
1 * 3 = 3 2 * 3 = 6 3 * 3 = 9 |
1 * 4 = 4 2 * 4 = 8 3 * 4 = 12 4 * 4 = 16 |
1 * 5 = 5 2 * 5 = 10 3 * 5 = 15 4 * 5 = 20 5 * 5 = 25 |
1 * 6 = 6 2 * 6 = 12 3 * 6 = 18 4 * 6 = 24 5 * 6 = 30 6 * 6 = 36 |
1 * 7 = 7 2 * 7 = 14 3 * 7 = 21 4 * 7 = 28 5 * 7 = 35 6 * 7 = 42 7 * 7 = 49 |
1 * 8 = 8 2 * 8 = 16 3 * 8 = 24 4 * 8 = 32 5 * 8 = 40 6 * 8 = 48 7 * 8 = 56 8 * 8 = 64 |
1 * 9 = 9 2 * 9 = 18 3 * 9 = 27 4 * 9 = 36 5 * 9 = 45 6 * 9 = 54 7 * 9 = 63 8 * 9 = 72 9 * 9 = 81 //源代码片段来自云代码http://yuncode.net |
|
初级程序员
by: 永远的希望 发表于:2016-07-06 14:24:24 顶(0) | 踩(0) 回复
谢谢分享
回复评论